OAKLAND -- With just nine games left in the regular season, the A's are in a great position to lock up a playoff berth for the second consecutive year.
Oakland sits atop the AL wild-card standings at 92-61, two games ahead of Tampa Bay and 2 1/2 games in front of Cleveland. The A's also have the easiest remaining schedule of the three clubs.
Here's a breakdown of each team's final three series and their odds to make the playoffs:
A's: 92-61 (9 games remaining)
3 vs. Rangers (74-79)
2 at Angels (69-83)
4 at Mariners (64-88)
Oakland will play its final nine games of the regular season against sub-.500 AL West opponents. With a magic number of eight to clinch the top-wild card position, the A's likely only need to win five of the nine games. A 6-3 record would just about guarantee them the top spot.
According to FanGraphs, the A's have a 96.3 percent chance of making the playoffs.
Rays: 90-63 (9 games remaining)
4 vs. Red Sox (79-72)
2 vs. Yankees (99-54)
3 at Blue Jays (61-91)
The Rays have the most difficult remaining schedule of the three wild-card contenders, with six games against the Red Sox and Yankees. New York still has something to play for as they try to beat out Houston for home-field advantage, while Boston's lineup is always dangerous.
FanGraphs gives Tampa Bay a 59.9 percent chance of making the playoffs.
Indians: 89-63 (10 games remaining)
1 vs. Tigers (45-106)
3 vs. Phillies (78-72)
3 at White Sox (66-86)
3 at Nationals (83-68)
The Indians have two tough series remaining as they battle the Phillies and Nationals from the NL East. Washington currently leads the NL wild-card race, while Philadelphia is three games out of the second spot.
According to FanGraphs, Cleveland has a 44.0 percent chance of making the playoffs.
The A's own tiebreakers against both the Rays and Indians, having won the season series against each club. That means, in the case of a two-team tie between the A's and either Tampa Bay or Cleveland, Oakland would still host the Wild Card Game.
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It gets more complicated if all three teams tie for the two wild-card positions. The A's still own the tiebreaker, so they would host the Rays, with the winner earning the top wild-card spot. The Indians would then host the loser, with the winner of that game claiming the second wild-card position.
Of course, if the A's handle their business, it won't come down to tiebreakers.